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A100800
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Let f(n) = n + sum of the digits of n. If f(n) is multiple of n then a(n)= f(n) else a(n) = f(f(f(n)))... until one gets a multiple of n; a(n) = 0 if no such number exists.
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3
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2, 4, 6, 8, 10, 12, 14, 16, 18, 130, 341, 24, 130, 392, 30, 320, 119, 36, 950, 80, 84, 88, 115, 96, 950, 104, 54, 392, 406, 120, 341, 736, 231, 578, 455, 72, 851, 950, 507, 320, 328, 210, 559, 440, 90, 184, 658, 480, 392, 950, 204, 416, 530, 162, 1430, 2128, 114
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OFFSET
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1,1
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COMMENTS
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Conjecture: No term is zero.
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LINKS
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EXAMPLE
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a(10) = 130, f(10) = 10 + 1 = 11, f(f(10)) = f(11) = 13,... we get the sequence 10,11,13,17,25,32,37,47,58,71,79,95,109,119,130,...
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CROSSREFS
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KEYWORD
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base,easy,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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