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Position of first occurrence of n in the fractional part of sqrt(2), starting with n=0.
0

%I #6 Feb 16 2025 08:32:55

%S 13,2,4,6,1,7,8,11,18,14,76,186,113,5,2,96,21,55,42,247,28,4,114,9,26,

%T 292,138,92,233,115,12,54,68,306,89,6,125,10,80,278,242,1,3,90,140,

%U 219,73,70,17,120,15,235,188,45,310,128,7,97,129,165,126,328,8,312,94,164

%N Position of first occurrence of n in the fractional part of sqrt(2), starting with n=0.

%H Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/PythagorassConstant.html">Pythagorass Constant</a>

%e The fractional part of sqrt(2) begins 4142135623730, so the first occurrence of 0 is at position 13; the first occurrence of 1 is at position 2; ...; the first occurrence of 14 is at position 2 and so on.

%Y Cf. A002193 for digits of sqrt(2).

%K base,easy,nonn,changed

%O 0,1

%A Mark Hudson (mrmarkhudson(AT)hotmail.com), Nov 04 2004