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A100050
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A Chebyshev transform of n.
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2
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0, 1, 2, 0, -4, -5, 0, 7, 8, 0, -10, -11, 0, 13, 14, 0, -16, -17, 0, 19, 20, 0, -22, -23, 0, 25, 26, 0, -28, -29, 0, 31, 32, 0, -34, -35, 0, 37, 38, 0, -40, -41, 0, 43, 44, 0, -46, -47, 0, 49, 50, 0, -52, -53, 0, 55, 56, 0, -58, -59, 0, 61, 62, 0, -64, -65, 0, 67, 68, 0, -70, -71, 0, 73, 74, 0, -76, -77, 0, 79, 80, 0, -82, -83, 0, 85, 86, 0
(list; graph; refs; listen; history; internal format)
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OFFSET
| 0,3
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COMMENTS
| A Chebyshev transform of x/(1-x)^2: if A(x) is the g.f. of a sequence, map it to ((1-x^2)/(1+x^2))A(x/(1+x^2)).
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LINKS
| M. Somos, Rational Function Multiplicative Coefficients
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FORMULA
| Euler transform of length 6 sequence [ 2, -3, -2, 0, 0, 2]. - Michael Somos Mar 19 2011
a(n) is multiplicative with a(2^e) = -(-2)^e if e>0, a(3^e) = 0^e, a(p^e) = p^e if p == 1 (mod 6), a(p^e) = (-p)^e if p == 5 (mod 6). - Michael Somos Mar 19 2011
G.f.: x * (1 - x^2)^3 * (1 - x^3)^2 / ((1 - x)^2 * (1 - x^6)^2) = x * (1 + x)^2 * (1 - x^2) / (1 + x^3)^2. - Michael Somos Mar 19 2011
a(3*n) = 0, a(3*n + 1) = (-1)^n * (3*n + 1), a(3*n + 2) = (-1)^n * (3*n + 2). a(-n) = a(n). - Michael Somos Mar 19 2011
G.f.: x(1-x^2)/(1-x+x^2)^2; a(n)=2a(n-1)-3a(n-2)+2a(n-3)-a(n-4); a(n)=n*sum{k=0..floor(n/2), (-1)^k*binomial(n-k, k)*(n-2k)/(n-k)}.
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EXAMPLE
| x + 2*x^2 - 4*x^4 - 5*x^5 + 7*x^7 + 8*x^8 - 10*x^10 - 11*x^11 + 13*x^13 + ...
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PROG
| sage: [lucas_number1(n, 2, 1)*lucas_number1(n, 1, 1) for n in xrange(0, 88)] - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jul 06 2008
(PARI) {a(n) = n * (-1)^(n\3) * sign( n%3)} /* Michael Somos Mar 19 2011 */
(PARI) {a(n) = local(A, p, e); if( abs(n)<1, 0, A = factor(abs(n)); prod( k=1, matsize(A)[1], if( p=A[k, 1], e=A[k, 2]; if( p==2, -(-2)^e, (kronecker( -12, p) * p)^e))))} /* Michael Somos Mar 19 2011 */
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CROSSREFS
| Cf. A099837, A099443, A011655, A100047, A100048, A100051, A091684.
Sequence in context: A070692 A091684 A162397 * A164616 A173335 A201837
Adjacent sequences: A100047 A100048 A100049 * A100051 A100052 A100053
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KEYWORD
| easy,sign,mult
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AUTHOR
| Paul Barry (pbarry(AT)wit.ie), Oct 31 2004
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