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A100036 a(n) = smallest m such that A100035(m) = n. 9
1, 2, 3, 5, 7, 12, 14, 23, 25, 38, 40, 57, 59, 80, 82, 107, 109, 138, 140, 173, 175, 212, 214, 255, 257, 302, 304, 353, 355, 408, 410, 467, 469, 530, 532, 597, 599, 668, 670, 743, 745, 822, 824, 905, 907, 992, 994, 1083, 1085, 1178, 1180, 1277, 1279, 1380 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,2

COMMENTS

Smallest positions of occurrences of the natural numbers as subsequence in A100035;

A100035(a(n)) = n and A100035(m) <> n for m < a(n);

a(n) < A100037(n) < A100038(n) < A100039(n).

LINKS

Table of n, a(n) for n=1..54.

FORMULA

Conjecture: a(n) = partial sums of sequence [1,1,1,2,2,5,2,9,2,13,2,17,2,21,2,25,2,29,2,33,...2,n/2-7,2,...]. In other words, a(n) consists of the numbers 1,2,3 and the sequences A096376 and A096376+2 interspersed. - Ralf Stephan, May 15 2007

EXAMPLE

First terms (10=A,11=B,12=C) of A100035(a(n)):

123.4.5....6.7........8.9............A.B................C.

1231435425165764736271879869584938291A9BA8B7A6B5A4B3A2B1CBD;

a(1) = A084849(1) = 1, A100035(1) = 1;

a(2) = A014107(1) = 2, A100035(2) = 2;

a(3) = A033537(1) = 3, A100035(3) = 3;

a(4) = A100040(1) = 5, A100035(5) = 4;

a(5) = A100041(1) = 7, A100035(7) = 5.

CROSSREFS

Sequence in context: A031216 A004683 A240305 * A179781 A309370 A022438

Adjacent sequences:  A100033 A100034 A100035 * A100037 A100038 A100039

KEYWORD

nonn

AUTHOR

Reinhard Zumkeller, Oct 31 2004

STATUS

approved

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Last modified October 22 17:29 EDT 2019. Contains 328319 sequences. (Running on oeis4.)