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A099776
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Length of the hypotenuse of an integer right triangle with the hypotenuse being one more than the longer side. The shorter sides are just consecutive odd numbers 3, 5, 7, ...
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5
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5, 13, 25, 41, 61, 85, 113, 145, 181, 221, 265, 313, 365, 421, 481, 545, 613, 685, 761, 841, 925, 1013, 1105, 1201, 1301, 1405, 1513, 1625, 1741, 1861, 1985, 2113, 2245, 2381, 2521, 2665, 2813, 2965, 3121, 3281, 3445, 3613, 3785, 3961, 4141, 4325, 4513
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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COMMENTS
| Largest hypotenuse of primitive Pythagorean triangles with inradius n. (For smallest hypotenuse of PPT with inradius n, see A087484) Essentially the same as A001844. - Lekraj Beedassy (blekraj(AT)yahoo.com), May 08 2006
The complete triple {X(n), Y(n), Z(n)=Y(n)+1}, with X<Y<Z, {X(n)=A005408(n);Y(n)=A046092(n), Z(n)=A001844(n)} may be recursively generated through the mapping W(n) -> M*W(n), where W(n) = transpose of vector [X(n) Y(n) Z(n)] and M a 3 X 3 matrix given by [1 -2 2 / 2 -1 2 / 2 -2 3 ]. Such triples correspond to successive number pair Pythagorean generators(p,q=p+1) yielding {X=p+q,Y=2p*q,Z=p^2 + q^2} - Lekraj Beedassy (blekraj(AT)yahoo.com), Jun 04 2006
sum of two consecutive squares: 1^4=5,4+9=13,9+16=25,16+25=41,.. [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Sep 25 2009]
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LINKS
| Index entries for sequences related to linear recurrences with constant coefficients, signature (3,-3,1).
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FORMULA
| a(n) = ((2*n+1)^2-1)/2 + 1
a(n)=4*n+a(n-1), (with a(1)=5) [From Vincenzo Librandi, Nov 17 2010]
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MATHEMATICA
| lst={}; Do[a=(n^2+(n+1)^2); AppendTo[lst, a], {n, 5!}]; lst [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Sep 25 2009]
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PROG
| (C) #include "stdio.h"
int main(int argc, char* argv[]){
unsigned int i;
for (i=1; i<50; i++)
printf ("%u, ", (((2*i+1)*(2*i+1)-1)/2)+1);
return 0;
}
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CROSSREFS
| Sequence in context: A081961 A096891 A001844 * A133322 A146590 A098483
Adjacent sequences: A099773 A099774 A099775 * A099777 A099778 A099779
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KEYWORD
| easy,nonn
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AUTHOR
| Nick Robins (nrobins(AT)hackettfreedman.com), Nov 12 2004
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