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A099726
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Sum of remainders of the n-th prime mod k, for k = 1,2,3,...,n.
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3
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0, 1, 3, 5, 7, 7, 14, 18, 28, 30, 31, 26, 38, 45, 63, 71, 93, 75, 96, 115, 101, 142, 161, 167, 152, 159, 203, 224, 219, 222, 216, 250, 263, 296, 341, 320, 319, 349, 433, 427, 496, 419, 487, 481, 538, 537, 495, 631, 635, 676, 697, 777, 665, 820, 784, 874, 929, 856
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OFFSET
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1,3
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LINKS
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FORMULA
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a(n) = n*p - A024916(p) + Sum_{k=n+1..p} k*floor(p/k), where p = prime(n). - Daniel Suteu, Feb 02 2021
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EXAMPLE
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a(7)=14 because the 7th prime is 17 and its remainders modulo 1,2,3,4,5,6,7 are 0,1,2,1,2,5,3 respectively and 0+1+2+1+2+5+3=14.
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MAPLE
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umpf:=n->add(modp(floor(ithprime(n)), m), m=1..n); seq(umpf(k), k=1..120);
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PROG
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(PARI) a(n) = my(p=prime(n)); sum(k=1, n, p%k); \\ Daniel Suteu, Feb 02 2021
(PARI)
T(n) = n*(n+1)/2;
S(n) = my(s=sqrtint(n)); sum(k=1, s, T(n\k) + k*(n\k)) - s*T(s); \\ A024916
g(a, b) = my(s=0); while(a <= b, my(t=b\a); my(u=b\t); s += t*(T(u) - T(a-1)); a = u+1); s;
a(n) = my(p=prime(n)); n*p - S(p) + g(n+1, p); \\ Daniel Suteu, Feb 02 2021
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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Joseph Biberstine (jrbibers(AT)indiana.edu), Nov 07 2004
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EXTENSIONS
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STATUS
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approved
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