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%I #19 Jan 25 2020 02:28:48
%S 1,4,1,16,12,2,64,112,48,6,256,960,800,240,24,1024,7936,11520,6240,
%T 1440,120,4096,64512,154112,134400,53760,10080,720,16384,520192,
%U 1978368,2612736,1612800,510720,80640,5040,65536,4177920,24780800
%N Triangle T(k,n) by rows: n! * A075499(k,n).
%C Triangle given by [4,0,8,0,12,0,16,0,20,0,24,0,28,0,...] DELTA [1,1,2,2,3,3,4,4,5,5,6,6,...] where DELTA is the operator defined in A084938. - _Philippe Deléham_, Jun 04 2009
%H Toufik Mansour, <a href="https://arxiv.org/abs/math/0301157">Generalization of some identities involving the Fibonacci numbers</a>, arXiv:math/0301157 [math.CO], 2003.
%F T(n, k) = A028246(n+1, k+1)*4^(n-k) = Stirling2(n+1, k+1)*k!*4^(n-k), see A008277. - _Philippe Deléham_, Oct 02 2005
%e Triangle begins:
%e 1;
%e 4, 1;
%e 16, 12, 2;
%e 64, 112, 48, 6;
%e 256, 960, 800, 240, 24;
%e 1024, 7936, 11520, 6240, 1440, 120;
%K nonn,tabl
%O 0,2
%A _Ralf Stephan_, Oct 21 2004
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