%I #10 Jan 07 2018 08:10:29
%S 1,1,1,2,1,2,5,5,5,5,14,7,7,7,14,42,42,21,21,42,42,132,22,44,33,44,22,
%T 132,429,429,143,429,429,143,429,429,1430,715,715,715,143,715,715,715,
%U 1430,4862,4862,2431,2431,2431,2431,2431,2431,4862,4862,16796,8398
%N Denominators of the inverse of a Catalan scaled binomial matrix.
%C First column and main diagonal are A000108. Row sums are A098510. Diagonal sums are A098511. Second column is A098512.
%F Triangle T(n, k)=denominator((n+1)binomial(n, k)/binomial(2n, n))
%e Rows begin
%e 1;
%e 1,1;
%e 2,1,2;
%e 5,5,5,5;
%e 14,7,7,7,14;
%e ...
%t T[n_, k_] := Denominator[(n + 1)*(Binomial[n, k]/Binomial[2*n, n])];
%t Table[T[n, k], {n, 0, 10}, {k, 0, n}] // Flatten (* _Jean-François Alcover_, Jan 07 2018 *)
%Y Cf. A098505, A098474.
%K easy,nonn,tabl
%O 0,4
%A _Paul Barry_, Sep 11 2004