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A098375
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(1/p)*abs(p*(p^(p-1)-1)*B(p-1)-1) when p runs through the primes and B(k) denotes the k-th Bernoulli's number.
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0
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1, 1, 21, 2801, 1964956409, 5897061106093, 345112805910366790769, 5724003102153474225966281, 5621496960287976955328551429580241, 2417009997194019381479073094599560492013039757981
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OFFSET
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1,3
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COMMENTS
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Conjecture: p is an odd prime iff p divides p*(p^(p-1)-1)*B(p-1)-1. Seems to be the equivalent (with integer moduli) to Agoh's conjecture (which involves rational moduli).
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LINKS
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PROG
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(PARI) a(n)=(1/prime(n))*(prime(n)*(prime(n)^(prime(n)-1)-1)*bernfrac(prime(n)-1)-1)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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