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FORMULA
| a(n) = (T(n, 7)-1)/6 with Chebyshev's polynomials of the first kind evaluated at x=7: T(n, 7) = A011943(n) = ((7+4*sqrt(3))^n + (7-4*sqrt(3))^n)/2; therefore: a(n) = ((7+4*sqrt(3))^n+(7-4*sqrt(3))^n-2)/12.
a(n) = A001353(n)^2 = S(n-1, 4)^2 with Chebyshev's polynomials of the second kind evaluated at x=4, S(n, 4):=U(n, 2).
a(n) = 14*a(n-1) - a(n-2) + 2, n>=2, a(0)=0, a(1)=1.
a(n) = 15*a(n-1) - 15*a(n-2) + a(n-3), n>=3, a(0)=0, a(1)=1, a(2)=16.
G.f.: x*(1+x)/((1-x)*(1-14*x+x^2)) = x*(1+x)/(1-15*x+15*x^2-x^3) (from the Stephan link, see A092184).
4*A007655(n+1) + A046184(n) = A055793(n+2) + a(n+1) (conjecture) - Creighton Dement (creighton.k.dement(AT)uni-oldenburg.de), Nov 01 2004
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