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A098229
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a(n)=6*c(n,1) where n runs through the 3-smooth numbers (see comment).
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0
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0, 3, 2, 3, 5, 3, 2, 5, 3, 5, 5, 2, 3, 5, 5, 5, 3, 5, 2, 5, 5, 3, 5, 5, 5, 5, 2, 3, 5, 5, 5, 5, 5, 3, 5, 5, 2, 5, 5, 5, 3, 5, 5, 5, 5, 5, 5, 3, 2, 5, 5, 5, 5, 5, 5, 3, 5, 5, 5, 5, 5, 2, 5, 5, 3, 5, 5, 5, 5, 5, 5, 5, 5, 3, 5, 5, 2, 5, 5, 5, 5, 5, 5, 3, 5, 5, 5, 5, 5, 5, 5, 5, 2, 5, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5
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OFFSET
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1,2
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COMMENTS
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If n is a 3-smooth number, (i.e. of form 2^i*3^j for i,j>=0) the value c(n,k)={(n^(2k)-1)*B(2k)} is independent of k where {x} denotes the fractional part of x and B(k) is the k-th Bernoulli's number.
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LINKS
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FORMULA
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a(1)=0; for k>0, a(2^k)=3 a(3^k)=2; for i>0 and j>0 a(2^i*3^j)=5
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PROG
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(PARI) m=7; for(n=1, 1000000, if(gcd(n, 6^100)==n, print1(6*frac((n^(2*m)-1)*bernfrac(2*m)), ", ")))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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