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A097220
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Numbers n such that pi(n) = product of digits of n.
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5
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16, 17, 63, 73, 364, 437, 545, 573, 963, 6475, 23797, 67458, 2475989, 2475998
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OFFSET
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1,1
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COMMENTS
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Next term is greater than 2*10^8. The only numbers with the property that pi(n) = sum of the digits of n, are the three numbers 15, 27 & 39.
a(15) > 10^15, if it exists. - Chai Wah Wu, Apr 23 2018
When n exceeds approximately 10^44, then pi(n) is consistently greater than the product of digits of n. So no term of this sequence exceeds 10^44. In particular, this sequence is finite. - Jeppe Stig Nielsen, Nov 04 2018
Products of digits of terms are in A002473. Term by term up to some bound (such that the bounds on primes hold), one could check terms t in A002473 on some known bounds. See example below. - David A. Corneth, Nov 06 2018
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LINKS
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EXAMPLE
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2475998 is in the sequence because pi(2475998)=2*4*7*5*9*9*8.
1152 is in A002473. As 8643 <= prime(1152) <= 9794. Examples of the 13 numbers with product of digits is 1152 in that interval are: 8944, 9288, 9448, 9484 none of which are terms. - David A. Corneth, Nov 06 2018
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MATHEMATICA
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v={}; Do[If[h=IntegerDigits[n]; l=Length[h]; p=Product[h[[k]], {k, l}]; PrimePi[n]==p, v=Append[v, n]; Print[v], If[Mod[n, 1000000]==0, Print[ -n]]], {n, 200000000}]
Select[Range[2500000], PrimePi[#]==Times@@IntegerDigits[#]&] (* Harvey P. Dale, Dec 04 2012 *)
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PROG
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(PARI) isok(n) = primepi(n) == factorback(digits(n)); \\ Michel Marcus, Apr 23 2018
(Magma) [n: n in [1..10^5] | &*Intseq((n)) eq #PrimesUpTo(n)]; // Vincenzo Librandi, Nov 06 2018
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CROSSREFS
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KEYWORD
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base,more,nonn,fini
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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