OFFSET
0,2
COMMENTS
a(n) = (6/5)*{1, 26, 26, 676, 676, 17576, ...} - 25*{0, 1, 0, 25, 0, 625, ...} - (1/5)*{1, 1, 1, 1, 1, 1, ...}.
LINKS
G. C. Greubel, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (1,51,-51,-650,650).
FORMULA
G.f.: (1 +5*x -26*x^2 -100*x^3)/((1-x)*(1-25*x^2)*(1-26*x^2)).
a(n) = (3/5)*((1-sqrt(26))*(-sqrt(26))^n + (1+sqrt(26))*(sqrt(26))^n) - (5/2)*(5^n - (-5)^n) - 1/5.
a(n) = a(n-1) + 51*a(n-2) - 51*a(n-3) - 650*a(n-4) + 650*a(n-5).
MAPLE
seq(coeff(series((1+5*x-26*x^2-100*x^3)/((1-x)*(1-25*x^2)*(1-26*x^2)), x, n+1), x, n), n = 0..30); # G. C. Greubel, Sep 17 2019
MATHEMATICA
CoefficientList[Series[(1+5*x-26*x^2-100*x^3)/((1-x)*(1-25*x^2)*(1- 26*x^2)), {x, 0, 30}], x] (* G. C. Greubel, Sep 17 2019 *)
LinearRecurrence[{1, 51, -51, -650, 650}, {1, 6, 31, 186, 811}, 30] (* Harvey P. Dale, Oct 27 2020 *)
PROG
(PARI) my(x='x+O('x^30)); Vec((1+5*x-26*x^2-100*x^3)/((1-x)*(1-25*x^2)*(1-26*x^2))) \\ G. C. Greubel, Sep 17 2019
(Magma) R<x>:=PowerSeriesRing(Rationals(), 20); Coefficients(R!( (1+5*x-26*x^2-100*x^3)/((1-x)*(1-25*x^2)*(1-26*x^2)) )); // G. C. Greubel, Sep 17 2019
(Sage)
def A097194_list(prec):
P.<x> = PowerSeriesRing(QQ, prec)
return P((1+5*x-26*x^2-100*x^3)/((1-x)*(1-25*x^2)*(1-26*x^2))).list()
A097194_list(20) # G. C. Greubel, Sep 17 2019
(GAP) a:=[1, 6, 31, 186, 811];; for n in [6..30] do a[n]:=a[n-1]+51*a[n-2] -51*a[n-3]-650*a[n-4]+650*a[n-5]; od; a; # G. C. Greubel, Sep 17 2019
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Jul 30 2004
STATUS
approved