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 A096773 a(n+2) = 4*a(n) + 1; a(1) = 0, a(2) = 3. 5
 0, 3, 1, 13, 5, 53, 21, 213, 85, 853, 341, 3413, 1365, 13653, 5461, 54613, 21845, 218453, 87381, 873813, 349525, 3495253, 1398101, 13981013, 5592405, 55924053, 22369621, 223696213, 89478485, 894784853, 357913941, 3579139413, 1431655765 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS Remainders for classes m of integers n (mod 2^(m+1)). After applying one Collatz (3x+1)-transformation to the so-classified integers the result can be written in two classes (mod 6) only. This classifying scheme covers all integers >0. With one 3x+1-transformation T(x;p) := x' = (3x+1)/2^p all numbers x, described in the form, with the free parameter i >= 0, x = i*2^N +a(N) result in x', describable by the two classes with the same parameter i: x' = i*6 + 1 (for odd N>2), or x' = i*6 + 5 (for even N). Thus x =  4*i +  3 -> x' = 6*i + 5, x =   8*i + 1 -> x' = 6*i + 1, x = 16*i + 13 -> x' = 6*i + 5, x =  32*i + 5 -> x' = 6*i + 1, x = 64*i + 53 -> x' = 6*i + 5, x = 128*i +21 -> x' = 6*i + 1, .... all with "i" as a free parameter >=0 covering all natural numbers LINKS Index entries for linear recurrences with constant coefficients, signature (1,4,-4). FORMULA a(2m) = (5*2^(2m-1) - 1)/3, a(2m-1) = (2^(2m-2)-1)/3. From Paul Curtz, Jul 01 2008; corrected by Bob Selcoe, Jul 28 2018: (Start) a(2n) = 10*a(2n-1) + 3. a(n+1) - 2*a(n) = A001045(n+2), signed. (End) a(n) = (2^(n-1)*(3 + 2*(-1)^n) - 1)/3. - L. Edson Jeffery, Jul 12 2015 a(2n) = A086893(2n), a(2n+1) = A086893(2n-1), n > 0. - Yosu Yurramendi, Jan 17 2017 G.f.: -x^2*(-3+2*x) / ( (x-1)*(2*x+1)*(2*x-1) ). - R. J. Mathar, Mar 07 2017 a(2n) = A072197(n-1), n > 0; a(2n+1) = A002450(n), n >= 0. - Yosu Yurramendi, Mar 07 2017 a(2n) = (A266753(n) + A004171(n-1))/2, a(2n+1) = (A266753(n) - A004171(n-1))/2, n > 0. - Yosu Yurramendi, Mar 07 2017 a(n) = least residue 2*3^(2^(n-4)-1) - 1 (mod 2^n), n >= 5. - Bob Selcoe, Jul 26 2018 EXAMPLE a(1) = (2^0-1)/3 =  0, a(2) = (5*2^1 - 1) / 3 =  3, a(3) = (2^2-1)/3 =  1, a(4) = (5*2^3 - 1) / 3 = 13, a(5) = (2^4-1)/3 =  5, a(6) = (5*2^5 - 1) / 3 = 53, a(7) = (2^6-1)/3 = 21. .... MATHEMATICA a[1] = 0; a[2] = 3; a[n_] := a[n] = 4a[n - 2] + 1; Table[ a[n], {n, 35}] (* Robert G. Wilson v, Aug 20 2004 *) Table[(2^(n - 1)*(3 + 2*(-1)^(n)) - 1)/3, {n, 10}] (* L. Edson Jeffery, Jul 12 2015 *) PROG (MAGMA) [(2^(n-1)*(3 + 2*(-1)^n) - 1)/3: n in [1..40]]; // Vincenzo Librandi, Jul 12 2015 CROSSREFS Bisections are A002450 & A072197. Sequence in context: A113139 A266577 A143411 * A118384 A258239 A133176 Adjacent sequences:  A096770 A096771 A096772 * A096774 A096775 A096776 KEYWORD easy,nonn AUTHOR Gottfried Helms, Aug 15 2004 STATUS approved

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Last modified October 16 20:35 EDT 2019. Contains 328103 sequences. (Running on oeis4.)