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%I #14 May 10 2014 11:41:41
%S 4,8,9,10,12,14,15,16,20,21,24,25,26,27,28,33,34,35,36,38,39,40,44,45,
%T 52,55,56,57,58,60,63,65,68,75,76,77,81,84,85,86,88,92,93,99,100,104,
%U 105,111,115,117,119
%N Numbers whose divisors can be permuted so that all sums of triple adjacent divisors are primes.
%C A096527(a(n)) > 0, complement of A096530.
%C Square of terms of A053182 are in this sequence. - _Michel Marcus_, May 08 2014
%e Divisors of 24 are {1,2,3,4,6,8,12,24}:
%e [2,8,3,12,4,1,24,6] -> (2+8+3,8+3+12,3+12+4,12+4+1,4+1+24,1+24+6) = (13,23,19,17,29,31): therefore 24 is a term.
%K nonn,more
%O 1,1
%A _Reinhard Zumkeller_, Jun 23 2004
%E a(30)-a(51) from _Michel Marcus_, May 03 2014
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