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A096383
Area of the Pythagorean triangle a = u^2 - v^2 (cf. A096382) when u=3, v=4,4,5,...
0
84, 240, 486, 840, 1320, 1944, 2730, 3696, 4860, 6240, 7854, 9720, 11856, 14280, 17010, 20064, 23460, 27216, 31350, 35880, 40824, 46200, 52026, 58320, 65100, 72384, 80190, 88536, 97440, 106920, 116994, 127680, 138996, 150960, 163590
OFFSET
2,1
COMMENTS
When u = 1 except for the leading zeros, we get A007531. Since sides a,b of Pythagorean triple triangles are of opposite parity, the area will always be an integer.
FORMULA
The area of a Pythagorean triangle of sides a < b < c is A = (1/2)*ab. Substituting a = u^2 - v^2, b = 2uv into A and simplifying, we get A = uv(v^2 - u^2).
a(n) = (n-3)*(n*3)*(n+3), n >= 3. - Zerinvary Lajos, Mar 05 2007
a(n)=4*a(n-1)-6*a(n-2)+4*a(n-3)- a(n-4); a(3)=84, a(4)=240, a(5)=486, a(6)=840. - Harvey P. Dale, Aug 28 2011
G.f.: (6*x*(5*x-16)+84)/(x-1)^4. - Harvey P. Dale, Aug 28 2011
MAPLE
seq((n-3)*(n*3)*(n+3), n=3..38); # Zerinvary Lajos, Mar 05 2007
MATHEMATICA
Table[(n-3)(3n)(n+3), {n, 4, 40}] (* or *) LinearRecurrence[{4, -6, 4, -1}, {84, 240, 486, 840}, 40] (* Harvey P. Dale, Aug 28 2011 *)
PROG
(PARI) areagen(n, u) = for(v=u+1, n, print1(u*v*(v^2-u^2)", "))
CROSSREFS
Cf. A007531.
Sequence in context: A219808 A219459 A112066 * A220043 A137210 A220009
KEYWORD
nonn,easy
AUTHOR
Cino Hilliard, Aug 05 2004
STATUS
approved