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A096297
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a[n] = a[n-1]+4*(a[n-1]-Floor[a[n-1]^(1/3)]^3).
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0
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3, 11, 23, 83, 159, 295, 611, 1007, 1035, 1175, 1875, 2463, 3527, 4135, 4291, 5071, 5703, 8863, 12315, 12907, 15867, 16835, 21675, 29643, 40215, 43859, 47795, 52351, 59143, 76227, 84783, 105887, 114143, 128347, 141735, 146243, 168783, 178415
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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COMMENTS
| A cubic version of the Weintraub recursion.
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REFERENCES
| Steven H. Weintraub, Amer. Math. Monthly, v 111, no. 6, 2004, page 528.
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MATHEMATICA
| digits=200 r=4 A=Mod[3, r] a[n_Integer?Positive] :=a[n] =a[n-1]+r*(a[n-1]-Floor[a[n-1]^(1/3)]^3) a[1] = A a0=Table[a[n], {n, 1, digits}]
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CROSSREFS
| Sequence in context: A032026 A158034 A002515 * A081857 A168163 A120088
Adjacent sequences: A096294 A096295 A096296 * A096298 A096299 A096300
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KEYWORD
| nonn
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AUTHOR
| Roger L. Bagula (rlbagulatftn(AT)yahoo.com), Jun 20 2004
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