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A095229
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a(1) = 1; a(n) = n multiplied by the concatenation of all previous terms.
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0
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OFFSET
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1,2
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COMMENTS
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a(n) >= 10^(2^(n-2)-1) (can be easily shown by induction).
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LINKS
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EXAMPLE
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Let n = 4. The previous terms are 1,2 and 36. Their concatenation is 1236. This number is multiplied by 4 and we get a(4) = 4944.
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MATHEMATICA
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a = {1}; For[n=2, n<10, n++, AppendTo[a, n*FromDigits[Flatten[IntegerDigits[a]]]]]; a
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CROSSREFS
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KEYWORD
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base,nonn,less
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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