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A095229
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a(1) = 1; a(n) = n multiplied by the concatenation of all previous terms.
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0
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OFFSET
| 1,2
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COMMENTS
| a(n) >= 10^(2^(n-2)-1) (can be easily shown by induction)
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EXAMPLE
| Let n = 4. The previous terms are 1,2 and 36. Their concatentation is 1236. This number is multiplied by 4 and we get a(4) = 4944.
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MATHEMATICA
| a = {1}; For[n=2, n<10, n++, AppendTo[a, n*FromDigits[Flatten[IntegerDigits[a]]]]]; a
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CROSSREFS
| Sequence in context: A200571 A203021 A001070 * A047832 A004003 A060739
Adjacent sequences: A095226 A095227 A095228 * A095230 A095231 A095232
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KEYWORD
| base,nonn,less
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AUTHOR
| Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Jun 11 2004
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EXTENSIONS
| Edited, corrected and extended by Stefan Steinerberger (stefan.steinerberger(AT)gmail.com), Jun 16 2007
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