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a(n) = floor(10^n/3^n).
1

%I #11 Sep 08 2022 08:45:13

%S 1,3,11,37,123,411,1371,4572,15241,50805,169350,564502,1881676,

%T 6272254,20907515,69691719,232305731,774352437,2581174791,8603915972,

%U 28679719907,95599066359,318663554532,1062211848441,3540706161472

%N a(n) = floor(10^n/3^n).

%H Vincenzo Librandi, <a href="/A094977/b094977.txt">Table of n, a(n) for n = 0..1000</a>

%t Table[ Floor[(10/3)^n], {n, 0, 30}]

%o (Magma) [Floor(10^n / 3^n): n in [0..30]]; // _Vincenzo Librandi_, Sep 08 2011

%Y Cf. A002379, A094969-A094999.

%K nonn,easy

%O 0,2

%A _Robert G. Wilson v_, May 26 2004