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A094779
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Let 2^k = smallest power of 2 >= binomial(n,[n/2]); a(n) = 2^k - binomial(n,[n/2]).
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1
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0, 0, 0, 1, 2, 6, 12, 29, 58, 2, 4, 50, 100, 332, 664, 1757, 3514, 8458, 16916, 38694, 77388, 171572, 343144, 745074, 1490148, 3188308, 6376616, 13496132, 26992264, 56658968, 113317936, 236330717, 472661434, 980680538, 1961361076, 4052366942, 8104733884
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