%I #11 Apr 30 2014 01:37:05
%S 2,2472973457,6115597639891380737
%N Primes of form 2^j + 223^j.
%C Expression 2^j + q^j below q = prime <= prime[130] provided always prime at j=0; or for j=1 if q is a lesser-twin-prime; or more rarely 3 or 4 primes [four ones at q=3,5,17,37,59,137,179,223,461]; never found 5 or more relevant primes and the corresponding exponents proved to be powers of 2. Formal proofs of observations wanted.
%C See comment by _Michael Somos_, Aug 27 2004 for proof that j must be zero or a power of 2. - _Robert Price_, Apr 30 2013
%C Since the number j must be zero or a power of 2, checked j being powers of two through 2^19. Thus a(5) > 10^2400000. Primes of this magnitude are rare (about 1 in 5.6 million), so chance of finding one is remote with today's computer algorithms and speeds. - _Robert Price_, Apr 30 2013
%e The relevant exponents are powers of 2: 0,4,8,128. a(4) = 2^128 + 223^128 = 382844.....1067137 (a prime with 301 decimal digits).
%Y Cf. A082101, A094473-A094485.
%K nonn,bref
%O 1,1
%A _Labos Elemer_, Jun 01 2004
%E Corrected by _T. D. Noe_, Nov 15 2006