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A094284
a(n) = A094283(n+1)/A094283(n).
4
5, 3, 3, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2
OFFSET
1,1
COMMENTS
From n >= 4 onward a(n) = 2. Outline of the proof by AK: As the sequence A094282 is forced to grow approximately like 2^n, it implies that the other terms in A094280 never "catch" the terms in A094282 and as the sum of the other elements on the n-th row of A094280 grows just polynomially (Cf. A006003), their contribution to the row sum is soon minimal and A094282 (with A094282(n+1)/A094282(n) tending to the limit 2, as n -> inf) defines solely the behavior of this sequence.
MATHEMATICA
a=FindSequenceFunction[Join[{5, 3, 3, 2}, Table[2, {102}]], n]; Table[a, {n, 1, 102}] (* Fred Daniel Kline, Apr 25 2022 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Amarnath Murthy, Apr 27 2004
EXTENSIONS
Edited and extended by Antti Karttunen, Aug 25 2006
STATUS
approved