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A093909
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Let f(k, n) be the product of n consecutive numbers beginning with k. Then a(n) = f(A093908(n))/f(1+n*(n-1)/2).
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1
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2, 2, 6, 533, 1272, 1184964, 2728058, 260460615543, 320989537045, 1535738687883866008870, 1660017145844820190523887765476, 1840693015476119977, 8050776919178289031383553134261340
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