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Given the infinite continued fraction (1+i)+((1+i)/(1+i)+((1+i)/((1+i)+...)))), where i is the square root of (-1), this is the denominator of the convergents.
2

%I #2 Mar 30 2012 17:31:00

%S 1,2,5,4,15,130,377,136,3145,3030,26269,18980,219413,21866,40725,

%T 331024,15306833,44237570,127848949,30790860,26045045,3086134658,

%U 8919094697,3222082760,3547425525,215297250946,622220603405,15502163092

%N Given the infinite continued fraction (1+i)+((1+i)/(1+i)+((1+i)/((1+i)+...)))), where i is the square root of (-1), this is the denominator of the convergents.

%t Table[ Denominator[ FromContinuedFraction[ Table[1 + I, {n}]]], {n, 30}]

%Y Cf. A091806, A091807, A091808, A091809, A093725, A093726.

%K frac,nonn

%O 1,2

%A _Robert G. Wilson v_, Mar 11 2004