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A093502
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a(1) = 2; for n > 1, choose a(n) so that there are a(n-1) primes > a(n-1) and <= a(n).
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0
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2, 5, 19, 103, 733, 6691, 76831, 1081429, 18242699, 361919671, 8309068723, 217809953467, 6445388418589, 213232943658197, 7821073506524401
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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FORMULA
| a(n) = prime(pi(a(n-1))+a(n-1)). - Vladeta Jovovic (vladeta(AT)eunet.rs), Jun 19 2004
a(1)=2, a(n) = next a(n-1)th prime after a(n-1). [From Zak Seidov (zakseidov(AT)yahoo.com), Mar 21 2009]
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EXAMPLE
| 19 follows 5 as there are 5 primes > 5 and up to 19 inclusive, (7,11,13,17,19).
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MATHEMATICA
| a[1] := 2; a[n_] := Prime[PrimePi[a[n - 1]] + a[n - 1]]; Table[a[n], {n, 1, 10}] - Stefan Steinerberger (stefan.steinerberger(AT)gmail.com), Apr 10 2006
NestList[Prime[PrimePi[ # ] + # ] &, 2, 13] [From Zak Seidov (zakseidov(AT)yahoo.com), Mar 21 2009]
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CROSSREFS
| Sequence in context: A020117 A054687 A076669 * A009311 A107882 A192445
Adjacent sequences: A093499 A093500 A093501 * A093503 A093504 A093505
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KEYWORD
| more,nonn
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AUTHOR
| Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Apr 17 2004
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EXTENSIONS
| One more term from Vladeta Jovovic (vladeta(AT)eunet.rs), Jun 19 2004
More terms from Stefan Steinerberger (stefan.steinerberger(AT)gmail.com), Apr 10 2006
a(14)=6445388418589 from Zak Seidov (zakseidov(AT)yahoo.com), Mar 21 2009
a(14)-a(15) from Donovan Johnson (donovan.johnson(AT)yahoo.com), Dec 08 2009
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