OFFSET
1,2
FORMULA
a(2n) = [sum_{i = 1..2n} A093498(i)]/n. a(2n+1) = [prod_{i = 1..2n+1} A093498(i)]^(1/(2n+1)). - David Wasserman, Oct 25 2006
CROSSREFS
KEYWORD
less,nonn
AUTHOR
Amarnath Murthy, Apr 17 2004
EXTENSIONS
More terms from David Wasserman, Oct 25 2006
STATUS
approved