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A091664 10-adic integer x=.....06619977392256259918212890624 satisfying x^3 = x. 14
4, 2, 6, 0, 9, 8, 2, 1, 2, 8, 1, 9, 9, 5, 2, 6, 5, 2, 2, 9, 3, 7, 7, 9, 9, 1, 6, 6, 0, 1, 4, 0, 0, 9, 0, 1, 6, 9, 8, 0, 3, 2, 3, 2, 4, 3, 2, 4, 7, 5, 5, 0, 0, 0, 1, 1, 8, 3, 6, 8, 0, 8, 5, 9, 0, 5, 6, 6, 1, 2, 6, 0, 0, 9, 8, 9, 0, 5, 8, 3, 9, 2, 0, 8, 9, 6, 1, 8, 0, 1, 9, 1, 3, 7, 0, 0, 3, 5, 9, 3 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,1

COMMENTS

Let a,b be integers defined in A018247, A018248 satisfying a^2=a, b^2=b, obviously a^3=a, b^3=b; let c,d,e,f be integers defined in A091661, A063006, A091663, A091664 then c^3=c, d^3=d, e^3=e, f^3=f, c+d=1, a+e=1, b+f=1, b+c=a, d+f=e, a+f=c, a=f+1, b=e+1, cd=-1, af=-1, gh=-1 where -1=.....999999999.

LINKS

Seiichi Manyama, Table of n, a(n) for n = 0..9999 (terms 0..999 from Paul D. Hanna)

FORMULA

x = r^2 where r=...1441224165530407839804103263499879186432 (A120817). x = 10-adic limit_{n->infty} 4^(5^n). - Paul D. Hanna, Jul 06 2006

For n > 0, a(n) = 9 - A018248(n) = A018247(n). - Seiichi Manyama, Jul 28 2017

EXAMPLE

x equals the limit of the (n+1) trailing digits of 4^(5^n):

4^(5^0)=(4), 4^(5^1)=10(24), 4^(5^2)=1125899906842(624), ...

x = ...0557423423230896109004106619977392256259918212890624.

MATHEMATICA

To calculate c, d, e, f use Mathematica algorithms for a, b and equations: c=a-b, d=1-c, e=b-1, f=a-1.

PROG

(PARI) {a(n)=local(b=4, v=[]); for(k=1, n+1, b=b^5%10^k; v=concat(v, (10*b\10^k))); v[n+1]} \\ Paul D. Hanna, Jul 06 2006

CROSSREFS

Cf. A018247, A018248, A120817, A120818, A091661, A063006, A091663.

Sequence in context: A141674 A178394 A266391 * A010317 A131749 A016515

Adjacent sequences:  A091661 A091662 A091663 * A091665 A091666 A091667

KEYWORD

base,nonn

AUTHOR

Edoardo Gueglio (egueglio(AT)yahoo.it), Jan 28 2004

STATUS

approved

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Last modified September 22 05:47 EDT 2019. Contains 327287 sequences. (Running on oeis4.)