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a(n) = F(n)^F(n-1), where F is the Fibonacci sequence A000045.
1

%I #16 Jul 05 2022 11:39:34

%S 0,1,1,2,9,125,32768,815730721,154472377739119461,

%T 144896287389534090178492559785984,

%U 148707010444932320126692907511838968493975698947906494140625,164607782908174441344270105333730757465593941470198419854718194253607242940724175602015628380155976898641449

%N a(n) = F(n)^F(n-1), where F is the Fibonacci sequence A000045.

%e a(5) = 5^3 = 125.

%t Last[#]^First[#]&/@Partition[Fibonacci[Range[-1,12]],2,1] (* _Harvey P. Dale_, Apr 16 2011 *)

%Y Cf. A000045, A008973, A090241.

%K easy,nonn

%O 0,4

%A _Felix Tubiana_, Jan 23 2004

%E Edited by _N. J. A. Sloane_, Sep 19 2007