OFFSET
3,2
COMMENTS
The sum of the reciprocals of the lower bound twin primes is convergent. Proof: If S1 = 1/3 + 1/5 + 1/11 + 1/17 . . . is divergent then S1 + (S2 = 1/5 + 1/7 + 1/13 + 1/19 . . .) is divergent. But S1+S2 = 1/3+1/5 + 1/5+1/7 + 1/11+1/13 ... was proved to be convergent by V. Brun in 1919. So S1 is not divergent and since it is not oscillating, it is convergent as stated.
EXAMPLE
1/3+1/5+1/11+1/17 = 1916/2805 and 1916 is the fourth entry in the table.
MATHEMATICA
Accumulate[1/Select[Partition[Prime[Range[50]], 2, 1], #[[2]]-#[[1]]==2&][[All, 1]]]//Numerator (* Harvey P. Dale, Jul 24 2017 *)
PROG
(PARI) \Sum of the reciprocals of lower bound of twin primes { p=1; for(y=1, n, z=sum(x=1, y, 1/twin[x]^p); print1(numerator(z)", ") ); print(); print(z+.0); } \Build a twin prime table of lower bounds. Run only once in a session savetwins(n) = { twin = vector(n); c=1; forprime(x=3, n*10, if(isprime(x+2), twin[c]=x; c++; ) ) }
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Cino Hilliard, Jan 23 2004
STATUS
approved