%I
%S 4,4,1,2,1,1,2,2,3,3,3,3,4,4,1,2,1,1,2,2,3,3,3,3,4,4,1,2,1,1,2,2,3,3,
%T 3,3,4,4,1,2,1,1,2,2,3,3,3,3,4,4,1,2,1,1,2,2,3,3,3,3,4,4,1,2,1,1,2,2,
%U 3,3,3,3,4,4,1,2,1,1,2,2,3,3,3,3,4,4,1,2,1,1,2,2,3,3,3,3
%N Period 12: repeat (4, 4, 1, 2, 1, 1, 2, 2, 3, 3, 3, 3).
%C Original definition: Number of syllables in English name of nth month, with comment: Period 12.
%C The original definition corresponds to the finite subsequence a(1)..a(12). (There is no 13th month of the year, and if "of the year" is omitted on purpose, then there's no reason that the 1st month be January: the first day of the currently used Gregorian calendar was October 15, 1582, so month 1 of our current calendar rather was October. Traditionally the first month was March, whence the names September, ..., December for the 7th, ..., 10th month, January thus being the 11th.)  _M. F. Hasler_, Feb 25 2018
%D Marilyn vos Savant (marilyn(AT)parade.com), column in Parade magazine, 2003.
%H <a href="/index/Ca#calendar">Index entries for sequences related to calendars</a>
%H <a href="/index/Periodic#12">Index entries for 12periodic sequences</a>
%F a(n) = (1/792)*(37*(n mod 12) + 29*((n+1) mod 12) + 29*((n+2) mod 12) + 29*((n+3) mod 12)  37*((n+4) mod 12) + 29*((n+5) mod 12)  37*((n+6) mod 12) + 29*((n+7) mod 12) + 95*((n+8) mod 12)  37*((n+9) mod 12) + 227*((n+10) mod 12) + 29*((n+11) mod 12)), with n >= 0.  _Paolo P. Lava_, Oct 22 2008
%e For example, January is pronounced with four syllables: January.
%o (PARI) a(n,s=[3,4,4,1,2,1,1,2,2,3,3,3])=s[n%12+1] \\ _M. F. Hasler_, Feb 25 2018
%Y Cf. A031189, A031139, A075774.
%K nonn,word
%O 1,1
%A Drexel Hallaway (drexel(AT)cs.columbia.edu), Jan 08 2004
%E Thanks to _Ray Chandler_ for supplying the explanation for this sequence.
%E Edited by _M. F. Hasler_, Feb 25 2018
