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A089132
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First prime in the progression (n!+m)/m.
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0
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2, 2, 3, 2, 2, 2, 103, 631, 3, 3, 3, 3, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 5, 5, 5, 5, 5, 5, 163, 23, 10778406912001, 149, 1153, 100801, 137, 19, 19, 19, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2
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OFFSET
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1,1
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COMMENTS
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m=n=200 in PARI program. It appears that for any base m there is an infinity of primes in the progression.
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LINKS
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PROG
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(PARI) nfactp2d2(n, m) = { for(k=1, m, for(x=1, n, y=floor((x!+ k)/k); if(isprime(y), print1(y", "); break) ) ) }
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CROSSREFS
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KEYWORD
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base,easy,nonn
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AUTHOR
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STATUS
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approved
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