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A089042
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Composite numbers such that all divisors >1 have the same number of 1's in binary representation.
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2
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4, 8, 9, 16, 32, 49, 64, 128, 133, 256, 259, 512, 961, 1024, 2048, 2059, 2449, 3713, 4096, 4681, 4867, 6169, 6241, 8192, 8401, 8773, 9353, 10261, 10561, 12307, 12449, 16129, 16384, 16459, 16531, 16771, 18467, 20491, 24649, 24721, 24961, 25217
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OFFSET
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1,1
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COMMENTS
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A000120(d)=constant for all d with 1<d<=a(n) and d|a(n).
Are there terms with more than 2 distinct prime factors?
No terms with omega(n)>2 up to 10000000. - Michel Marcus, Jun 05 2013
The only term divisible by 3 is 9.
The terms divisible by 2 are 2^k for k > 1.
There are no terms divisible by 5. (End)
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LINKS
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EXAMPLE
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Divisors >1 of 259: 7, 37 and 259, which have all three 1's in binary: 7->'111', 37->'100101' and 259->'100000011', therefore 259 is a term.
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MAPLE
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A000120:= proc(n) convert(convert(n, base, 2), `+`) end proc:
filter:= proc(n) local t, f;
if isprime(n) then return false fi;
if n::even then return evalb(n = 2^ilog2(n)) fi;
if n mod 3 = 0 then return evalb(n = 9) fi;
for f in numtheory:-divisors(n) minus {1, n} do
if A000120(f) <> t then return false fi;
od;
true
end proc:
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MATHEMATICA
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dn1Q[n_]:=!PrimeQ[n]&&Length[Union[(DigitCount[#, 2, 1]&/@Rest[Divisors[ n]])]] == 1; Select[Range[26000], dn1Q] (* Harvey P. Dale, Oct 03 2013 *)
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PROG
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(PARI) isok(n) = {if (isprime(n) || n==1, return (0), my(nb = norml2(binary(n))); fordiv(n, d, if (d!=1 && norml2(binary(d)) != nb, return (0))); return (1); ); } \\ Michel Marcus, Jun 05 2013
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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