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A087295 Successive remainders when computing the euclidean algorithm for (n,m) where m is any positive integer having no common factor with n, gives a list ending with a sublist of Fibonacci sequence. Find m such that this sublist has the greatest length and define a(n) as this length. 0
0, 0, 1, 2, 1, 3, 1, 2, 4, 2, 1, 3, 2, 5, 3, 2, 2, 3, 4, 3, 3, 6, 2, 4, 2, 3, 3, 3, 4, 5, 3, 4, 3, 4, 7, 3, 3, 5, 4, 3, 2, 4, 2, 4, 4, 5, 3, 6, 4, 4, 5, 4, 3, 5, 3, 8, 3, 4, 4, 4, 6, 5, 3, 4, 4, 3, 5, 4, 4, 5, 4, 5, 3, 6, 4, 4, 7, 5, 4, 5, 4, 6, 5, 4, 3, 5, 6, 4, 4, 9, 3, 4, 5, 5, 4, 5, 4, 7, 5, 6, 4, 5, 3, 5, 4 (list; graph; refs; listen; history; internal format)
OFFSET

0,4

EXAMPLE

a(5) = 3 because computing euclidean algorithm for (5,8) gives 3, 2, 1 as successive remainders, all three belonging to Fibonacci sequence.

CROSSREFS

Sequence in context: A169896 A162306 A027750 * A175344 A130517 A056951

Adjacent sequences:  A087292 A087293 A087294 * A087296 A087297 A087298

KEYWORD

easy,nonn

AUTHOR

Thomas Baruchel (baruchel(AT)users.sourceforge.net), Oct 19 2003

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Last modified February 15 17:40 EST 2012. Contains 205828 sequences.