login
This site is supported by donations to The OEIS Foundation.
Logo

Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A086902 a(n) = 7a(n-1) + a(n-2), starting with a(0) = 2 and a(1) = 7, a(n) = [(7+sqrt(53))/2]^n + [(7-sqrt(53))/2]^n. 18
2, 7, 51, 364, 2599, 18557, 132498, 946043, 6754799, 48229636, 344362251, 2458765393, 17555720002, 125348805407, 894997357851, 6390330310364, 45627309530399, 325781497023157, 2326097788692498, 16608466017870643 (list; graph; refs; listen; history; internal format)
OFFSET

0,1

COMMENTS

a(n+1)/a(n) converges to (7+sqrt(53))/2 = 7.14005... a(0)/a(1)=2/7; a(1)/a(2)=7/51; a(2)/a(3)=51/364; a(3)/a(4)=364/2599; ... etc. Lim a(n)/a(n+1) as n approaches infinity = 0.1400549... = 2/(7+sqrt(53)) = (sqrt(53)-7)/2.

Contribution from Johannes W. Meijer (meijgia(AT)hotmail.com), Jun 12 2010: (Start)

In general sequences with recurrence a(n) = k*a(n-1)+a(n-2) with a(0)=2 and a(1)=k [and a(-1)=0] have generating function (2-k*x)/(1-k*x-x^2). If k is odd (k>=3) they satisfy a(3n+1) = b(5n), a(3n+2)=b(5*n+3), a(3n+3)=2*b(5n+4) where b(n) is the sequence of numerators of continued fraction convergents to sqrt(k^2+4). [If k is even then a(n)/2, for n>=1, is the sequence of numerators of continued fraction convergents to sqrt(k^2/4+1).]

For the sequence given above k=7 which implies that it is associated with A041090.

For a similar statement about sequences with recurrence a(n) = k*a(n-1)+a(n-2) but with a(0)=1 [and a(-1)=0] see A054413; a sequence that is associated with A041091.

For more information follow the Khovanova link and see A087130, A140455 and A178765.

(End)

LINKS

Index entries for sequences related to linear recurrences with constant coefficients

Tanya Khovanova, Recursive Sequences

Index entries for recurrences a(n) = k*a(n - 1) +/- a(n - 2)

Index entries for sequences related to Chebyshev polynomials.

FORMULA

a(n) = 7a(n-1) + a(n-2), starting with a(0) = 2 and a(1) = 7, a(n) = [(7+sqrt(53))/2]^n + [(7-sqrt(53))/2]^n.

E.g.f. : 2exp(7x/2)cosh(sqrt(53)x/2); a(n)=2^(1-n)sum{k=0..floor(n/2), C(n, 2k)53^k7^(n-2k)}. a(n)=2T(n, 7i/2)(-i)^n with T(n, x) Chebyshev's polynomials of the first kind (see A053120) and i^2=-1. - Paul Barry (pbarry(AT)wit.ie), Nov 15 2003

G.f.: (2-7x)/(1-7x-x^2). [From Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Nov 16 2008]

Contribution from Johannes W. Meijer (meijgia(AT)hotmail.com), Jun 12 2010: (Start)

a(2n+1) = 7*A097837(n), a(2n) = A099368(n).

a(3n+1) = A041090(5n), a(3n+2) = A041090(5*n+3), a(3n+3) = 2*A041090(5n+4).

Limit(a(n+k)/a(k), k=infinity) = (A086902(n) + A054413(n-1)*sqrt(53))/2.

Limit(A086902(n)/A054413(n-1), n=infinity) = sqrt(53).

(End)

EXAMPLE

a(4) = 2599 = 7a(3) + a(2) = 7*364 + 51 = [(7+sqrt(53))/2]^4 + [(7-sqrt(53))/2]^4 =

2598.999615 + 0.000385 = 2599

CROSSREFS

Cf. A058316.

Contribution from Johannes W. Meijer (meijgia(AT)hotmail.com), Jun 12 2010: (Start)

Cf. A000032 (k=1), A006497 (k=3), A087130 (k=5), A086902 (k=7), A087798 (k=9), A001946 (k=11), A088316 (k=13), A090301 (k=15), A090306 (k=17).

(End)

Sequence in context: A186860 A139008 A058721 * A138737 A046662 A118191

Adjacent sequences:  A086899 A086900 A086901 * A086903 A086904 A086905

KEYWORD

easy,nonn

AUTHOR

Nikolay V. Kosinov (kosinov(AT)unitron.com.ua), Sep 18 2003

EXTENSIONS

More terms from Ray Chandler (rayjchandler(AT)sbcglobal.net), Feb 14 2004

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Transforms | Puzzles | Hot | Classics
Recent Additions | More pages | Superseeker | Maintained by The OEIS Foundation Inc.

Content is available under The OEIS End-User License Agreement .

Last modified February 17 20:50 EST 2012. Contains 206085 sequences.