OFFSET
1,2
FORMULA
For n>=2: a(n) = Product_{j=0..n-2} (3^n - 3^j)^2 / (3^(n-1)- 3^j).
a(n) = ((3^n-1)/2)*Product_{j=0..n-2} (3^n-3^j). - David Wasserman, Mar 28 2005
MATHEMATICA
Table[3^(n^2) * (1 - 1/3^n) * QPochhammer[1/3^n, 3, n-1]/2, {n, 1, 10}] (* Vaclav Kotesovec, Apr 14 2024 *)
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Yuval Dekel (dekelyuval(AT)hotmail.com), Jul 31 2003
EXTENSIONS
More terms from David Wasserman, Mar 28 2005
STATUS
approved