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A085887
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Let r and s be such that r + s = n; a(n) = minimum value of tau(r) + tau(s).
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2
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2, 3, 3, 4, 3, 4, 3, 4, 4, 5, 3, 4, 3, 4, 4, 5, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 6, 3, 4, 3, 4, 4, 5, 4, 6, 3, 4, 4, 5, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 6, 3, 4, 4, 5, 4, 5, 3, 4, 3, 4, 4, 5, 4, 6, 3, 4, 4, 5, 3, 4, 3, 4, 4, 5, 4, 6, 3, 4, 4, 5, 3, 4, 4, 5, 4, 6, 3, 4, 4, 5, 4, 5, 4, 6, 3, 4, 4, 5, 3, 4, 3, 4, 4
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OFFSET
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2,1
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COMMENTS
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a(p+1) = 3 if p is a prime. a(n) = 4 if n is the sum of two primes. For all even numbers > 4, a(n) = 4 by Goldbach's conjecture.
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LINKS
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EXAMPLE
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a(8) = 3, the partitions are (1,7), (2,6), (3,5), (4,4) which give 3, 6, 4 and 6 as the sum of the number of divisors of both parts.
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MATHEMATICA
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Table[Min[Total/@DivisorSigma[0, IntegerPartitions[n, {2}]]], {n, 2, 120}] (* Harvey P. Dale, Mar 18 2023 *)
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PROG
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(PARI) A085887(n) = { my(m=0, k); for(r=1, n-1, if((m > k=(numdiv(r)+numdiv(n-r)))||!m, m = k)); m; }; \\ Antti Karttunen, Dec 14 2017
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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