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a(n) = n^(2n+1).
5

%I #16 Nov 02 2022 10:29:33

%S 0,1,32,2187,262144,48828125,13060694016,4747561509943,

%T 2251799813685248,1350851717672992089,1000000000000000000000,

%U 895430243255237372246531,953962166440690129601298432,1192533292512492016559195008117,1728673739677471101567216945987584,2876265888493261300027370452880859375

%N a(n) = n^(2n+1).

%H G. C. Greubel, <a href="/A085526/b085526.txt">Table of n, a(n) for n = 0..200</a>

%F a(n) = n*A062206(n). - _R. J. Mathar_, Mar 11 2017

%F a(n) = [x^(2*n+1)] 1/(1 - n*x). - _Ilya Gutkovskiy_, Oct 10 2017

%F a(n) = A089072(2*n-1, n-1). - _G. C. Greubel_, Nov 01 2022

%t Table[n^(2*n+1),{n,0,20}] (* _Vladimir Joseph Stephan Orlovsky_, Apr 19 2011 *)

%o (Magma) [n^(2*n+1): n in [0..30]]; // _G. C. Greubel_, Nov 01 2022

%o (SageMath) [n^(2*n+1) for n in range(31)] # _G. C. Greubel_, Nov 01 2022

%Y Cf. A062206, A089072.

%K nonn,easy

%O 0,3

%A _N. J. A. Sloane_, Jul 05 2003