|
|
A085069
|
|
a(1) =1, then the smallest number a(n)== 1 ( mod a(n-1)) such that tau(a(n))= n.
|
|
1
|
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
a(11) = (2*a(10)-1)^10, which is about 1.4*10^150, too large to include. - David Wasserman, Jan 20 2005
|
|
LINKS
|
|
|
EXAMPLE
|
a(4) = 10, a(5) = 81 == 1 (mod 10) and tau(81) = 5.
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|