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A084819
Least integers that satisfy Sum_{n>=1} 1/a(n)^z = 0, where a(1)=1, a(n+1) > a(n) and z = i*Pi/(4*log(2)).
0
1, 7, 18, 51, 147, 423, 1224, 3543, 10254
OFFSET
1,2
COMMENTS
Sequence satisfies Sum_{n>=1} 1/a(n)^z = 0 by requiring that the moduli of the successive partial sums are monotonically decreasing in magnitude for the given z.
PROG
(PARI) S=0; w=1; a=0; for(n=1, 100, b=a+1; while(abs(S+exp(-z*log(b)))>w, b++); S=S+exp(-z*log(b)); w=abs(S); a=b; print1(b, ", "))
KEYWORD
nonn,more
AUTHOR
Paul D. Hanna, Jun 04 2003
STATUS
approved