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A084229
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Let b(1)=1, b(2)=2, b(n) = sum of digits of b(1)+b(2)+b(3)+...+b(n-1), sequence gives values of n such that b(n)=3.
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0
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3, 5, 7, 9, 17, 19, 27, 29, 87, 95, 97, 159, 591, 599, 601, 663, 1143, 4609, 4617, 4619, 4681, 5161
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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COMMENTS
| b(k)==0 (mod 3) n>2.
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FORMULA
| Conjecture : a(n)/n^3 is bounded.
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PROG
| (PARI) // sumdig(n)=sum(k=0, ceil(log(n)/log(10)), floor(n/10^k)%10) // an=vector(10000); a(n)=if(n<0, 0, an[n]) // an[1]=1; an[2]=2; for(n=3, 5300, an[n]=sumdig(sum(k=1, n-1, a(k)))) // for(n=1, 5300, if(a(n)==3, print1(n, ", ")))
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CROSSREFS
| Cf. A065075.
Sequence in context: A117913 A064411 A146556 * A191356 A144753 A057482
Adjacent sequences: A084226 A084227 A084228 * A084230 A084231 A084232
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KEYWORD
| base,nonn
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AUTHOR
| Benoit Cloitre (benoit7848c(AT)orange.fr), Jun 21 2003
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