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A084214 Inverse binomial transform of a math magic problem. 10
1, 1, 4, 6, 14, 26, 54, 106, 214, 426, 854, 1706, 3414, 6826, 13654, 27306, 54614, 109226, 218454, 436906, 873814, 1747626, 3495254, 6990506, 13981014, 27962026, 55924054, 111848106, 223696214, 447392426, 894784854, 1789569706, 3579139414 (list; graph; refs; listen; history; internal format)
OFFSET

0,3

COMMENTS

Inverse binomial transform of A060816.

LINKS

Vincenzo Librandi, Table of n, a(n) for n = 0..1000

Index to sequences with linear recurrences with constant coefficients, signature (1,2)

FORMULA

a(n)=(5*2^n-3*0^n+4*(-1)^n)/6.

G.f.: (1+x^2)/((1+x)*(1-2*x)).

E.g.f.: (5*exp(2*x)-3*exp(0)+4*exp(-x))/6.

The binomial transform of A084214(n+1) is A020989(n). a(n)=A001045(n-1)+A001045(n+1)-0^n/2. - Paul Barry (pbarry(AT)wit.ie), May 04 2004

a(n)=sum{k=0..n, A001045(n+1)C(1, k/2)(1+(-1)^k)/2} - Paul Barry (pbarry(AT)wit.ie), Oct 15 2004

a(n) = a(n-1)+2*a(n-2) for n > 2. [From Klaus Brockhaus (klaus-brockhaus(AT)t-online.de), Dec 01 2009]

MAPLE

a[0]:=1:a[1]:=4:for n from 2 to 50 do a[n]:=a[n-1]+2*a[n-2]od: seq(a[n], n=-1..31); # [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Dec 15 2008]

MATHEMATICA

f[n_]:=2/(n+1); x=3; Table[x=f[x]; Numerator[x], {n, 0, 5!}] [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Mar 12 2010]

PROG

(MAGMA) [(5*2^n-3*0^n+4*(-1)^n)/6: n in [0..35]]; // Vincenzo Librandi, Jun 15 2011

(Haskell)

a084214 n = a084214_list !! n

a084214_list = 1 : xs where

   xs = 1 : 4 : zipWith (+) (map (* 2) xs) (tail xs)

-- Reinhard Zumkeller, Aug 01 2011

CROSSREFS

Cf. A048654.

Sequence in context: A200186 A192782 A188576 * A030138 A009849 A103419

Adjacent sequences:  A084211 A084212 A084213 * A084215 A084216 A084217

KEYWORD

easy,nonn

AUTHOR

Paul Barry (pbarry(AT)wit.ie), May 19 2003

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Last modified February 15 12:25 EST 2012. Contains 205786 sequences.