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%I #14 Mar 23 2016 11:26:33
%S 1,3,55,43631,99515655135,4723258824886629604131775,
%T 589359179694820074404152604620573424809709490316113791,
%U 13331474848620898858862175943355927686887898121894707763190978243005066121710225087713374054319814910927464555589375
%N a(1)=1 then a(n) is the least k>=1 such that the nested radical sqrt(a(1)^2+sqrt(a(2)^2+sqrt(a(3)^2+(....+sqrt(a(n)^2)))...) is an integer.
%F n = sqrt(a(1)^2+sqrt(a(2)^2+sqrt(a(3)^2+(....+sqrt(a(n)^2)))...).
%F Equals main diagonal of triangle A166994. [_Paul D. Hanna_, Nov 18 2009]
%e k=55 is the least integer such that sqrt(1^2+sqrt(3^2+sqrt(k^2)))=3 is an integer hence a(3)=55.
%Y Cf. A166994. [_Paul D. Hanna_, Nov 18 2009]
%K nonn
%O 1,2
%A _Benoit Cloitre_, Jun 18 2003
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