%I #17 Sep 08 2022 08:45:10
%S 6,21,105,301,1221,2041,4641,6517,11661,23577,28861,49321,67281,77701,
%T 101661,146121,201957,223321,296341,352941,383761,486877,564981,
%U 697137,903361,1020201,1082221,1213701,1283257,1430241,2032381,2231061,2552721,2666437
%N p(p^2-p+1) as p runs through the primes.
%C Warning: not all quizzes permit the use of the OEIS!
%C Discard (from the list of integers) numbers that have exactly 1 factor of prime(n) in their prime factorization. Of those remaining, the proportion that have exactly 2 factors of prime(n) is (prime(n)-1)/a(n). - _Peter Munn_, Nov 27 2020
%H Vincenzo Librandi, <a href="/A083558/b083558.txt">Table of n, a(n) for n = 1..1000</a>
%F a(n) = A000040(n) * A119959(n). - _Peter Munn_, Nov 29 2020
%t Table[p(p^2-p+1),{p,Prime[Range[40]]}] (* _Harvey P. Dale_, Jan 09 2017 *)
%o (Magma) [p*(p^2-p+1): p in PrimesUpTo(150)]; // _Vincenzo Librandi_, Jan 10 2017
%Y Cf. A000040, A119959.
%K nonn
%O 1,1
%A _N. J. A. Sloane_, Jun 15 2003