%I #11 Jul 04 2017 10:15:45
%S 0,9,102,1047,10486,103335,993462,9013959,68064390,
%T 1010101009101010101,101010100984163585500,10101010100267092639413,
%U 1010101010077712015887620,101010101009307295327755957
%N a(n) = (n times concatenation of n - n^n) divided by n, or a(n) = A083451(n) /n.
%C Conjecture: All the terms are all positive for n>1. (n times concatenation of n with itself > n^n), n>1.
%H Harvey P. Dale, <a href="/A083452/b083452.txt">Table of n, a(n) for n = 1..334</a>
%e a(4) = (4444 -4^4)/4 = 1047.
%t Table[(FromDigits[Flatten[IntegerDigits/@PadRight[{},n,n]]]-n^n)/n,{n,20}] (* _Harvey P. Dale_, Jul 04 2017 *)
%Y Cf. A083451.
%K base,nonn
%O 1,2
%A _Amarnath Murthy_ and Meenakshi Srikanth (menakan_s(AT)yahoo.com), May 01 2003
%E More terms from _David Wasserman_, Nov 10 2004