1,1

Conjecture: for any k >= 1 there will always be a brilliant constellation of the form {n, 2k+n} for some n. (True for all k <= 5000.)

Table of n, a(n) for n=1..61.

a(9)=169 because 169=13*13 and 169+18=11*17.

Cf. A078972, A083284, A083285.

Sequence in context: A010711 A168428 A127018 * A142973 A181110 A199959

Adjacent sequences: A083393 A083394 A083395 * A083397 A083398 A083399

base,nonn

Jason Earls, Jun 06 2003

approved