%I #8 Sep 25 2019 04:22:11
%S 23,11,91,11,234,9901,11,9091,511858,999001,101,99009901,99990001,
%T 9999900001,10001,99990001,99999990000001
%N a(n) = A083153(n+1)/A083153(n).
%Y Cf. A083153.
%K nonn,base,more
%O 1,1
%A _Amarnath Murthy_ and Meenakshi Srikanth (menakan_s(AT)yahoo.com), Apr 25 2003
%E More terms from _Patrick De Geest_, Jun 05 2003
%E a(13)-a(17) from _Giovanni Resta_, Sep 25 2019