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A082995
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Distance from n!+1 to next larger square.
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1
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2, 1, 2, 0, 0, 8, 0, 80, 728, 224, 323, 39168, 82943, 176399, 215295, 3444735, 26167683, 114349224, 255004928, 1158920360, 11638526760, 42128246888, 191052974115, 97216010328, 2430400258224, 1553580508515, 4666092737475
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OFFSET
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1,1
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COMMENTS
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The only known values of n such that n!+1 is a perfect square are 4, 5 and 7. Paul Leyland, et al. have found no other solutions for n <= 1 million (see link). For 1 <= n <= 11, n!+1 is within 1000 of being a square. Is there another n such that n!+1 <= "1000 away" from being a perfect square?
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LINKS
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EXAMPLE
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a(5)=0 because 5!+1 is a square.
a(8)=80 because 8!+1 = 40321 and the next larger square is 40401, so 40401-40321 = 80.
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MATHEMATICA
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a[n_] := Ceiling @ Sqrt[(f = n! + 1)]^2 - f; Array[a, 27] (* Amiram Eldar, Dec 14 2019 *)
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PROG
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(PARI) for(k=1, 27, print1(ceil(sqrt(k!+1))^2-(k!+1), ", ")) \\ Hugo Pfoertner, Dec 14 2019
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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