%I
%S 1,1,4,1,2,4,8,1,1,2,4,4,2,8,8,1,2,1,4,2,32,4,8,4,1,2,8,8,2,8,32,1,16,
%T 2,16,1,2,4,8,2,2,32,4,4,2,8,16,4,1,1,8,2,2,8,8,8,16,2,4,8,2,32,8,1,4,
%U 16,4,2,32,16,8,1,2,2,4,4,32,8,16,2,1,2,4,32,4,4,8,4,2,2,16,8,128,16,8,4,2
%N a(n)=gcd[2^n, sigma(1,n)]=gcd[A000079(n), A000203(n)] also a(n)=gcd[2^n, sigma(3,n)]=gcd[A000079(n), A001158(n)] These 2 definitions seems to be equivalent. Needs proof.
%Y Cf. A000203, A001157, A001158, A082902.
%K nonn,mult
%O 1,3
%A _Labos Elemer_, Apr 22 2003
