%I
%S 3,1,3,0,4,9,0,2,4,0,2,9,8,2,5,6,3,3,2,4,4,6,5,5,2,5,0,9,3,0,5,0,1,3,
%T 9,5,3,2,3,4,0,8,4,9,9,7,0,1,1,2,6,8,3,7,4,8,6,8,7,4,9,7,4,7,4,2,2,9,
%U 0,0,4,3,3,0,5,6,5,8,6,5
%N Consider f(m) = Sum{k=1..m} k! (A007489) when m is very large; a(n) = nth digit from end.
%C Apart from the first term, the same as A025016. [From _R. J. Mathar_, Sep 17 2008]
%e Example: Sum[n!,{n,1,30}] =274410818470142134209703780940313.
%e The last 7 digits in reverse order would give us first 7 terms of this sequence 3,1,3,0,4,9,0.
%e Take[Reverse[IntegerDigits[Sum[n!,{n,1,30}]]],7] {3,1,3,0,4,9,0}
%t Take[Reverse[IntegerDigits[Sum[n!, {n, 1, 500}]]], 100]  generates first 100 terms.
%Y Cf. A007489, A003422.
%K easy,base,nonn
%O 1,1
%A _Alexander Adamchuk_, May 15 2003
