OFFSET
0,4
FORMULA
a(n) = floor(n^3/(2n+1)). - Gary Detlefs, Feb 11 2010
a(n) = (4*n!/(n-2)!+2*n-3+(-1)^n+(-1)^(n/2)-(-1)^((n+1)/2)+(-1)^(-n/2)-(-1)^(-(n+1)/2))/8. - Wesley Ivan Hurt, May 19 2016
MAPLE
seq(floor(n^3/(2*n+1)), n=0..25); # Gary Detlefs, Feb 11 2010
MATHEMATICA
Table[Floor[n^3/(2 n + 1)], {n, 0, 60}] (* Wesley Ivan Hurt, May 19 2016 *)
PROG
(Magma) [Floor(n^3/(2*n+1)) : n in [0..60]]; // Wesley Ivan Hurt, May 19 2016
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, May 16 2003
STATUS
approved